log 2(3) = x
log 2(9) ?
Log2(72) = log2(2^3*3^2) = log2(2^3) + log2(3^2) = 3 + 2log2(3) = 3 + 2xlog2(6) = log2(2*3) = log2(3) + log2(1) = x+1
Consequently, we must have: log72(6)= log2(6)/log2(72)= (x+1)/(2x+3)
Edited on March 15, 2008, 4:54 am
blackjack
<a href="http://c.casalemedia.com/c?s=51816&f=3&id=0" target="_blank"><img src="http://as.casalemedia.com/s?s=51816&u=http://perplexus.info&f=3&id=0&if=0" width="120" height="600" border="0"></a>
flooble's webmaster puzzle
re(2): how about this one? :p
