log 2(3) = x
log 2(9) ?
In general, log_(2^a + 3^b) (2^c + 3^d)
= (log_2(log 2^c) + log_2(3^d))/(log_2(log 2^a) + log_2(3^b))
= (c + d*log_2(3))/(a + b*log_2(3))
= (c + dx)/(a+ bx)
blackjack
<a href="http://c.casalemedia.com/c?s=51816&f=3&id=0" target="_blank"><img src="http://as.casalemedia.com/s?s=51816&u=http://perplexus.info&f=3&id=0&if=0" width="120" height="600" border="0"></a>
flooble's webmaster puzzle
re(2): how about this one? :p : Generalised Case
