All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
3 and 4-digit numbers (Posted on 2017-07-17) Difficulty: 2 of 5
Consider the number 4808
Notice: 4^2+8^2=80
i.e. the sum of the squares of this number's first and last digits equals the number obtained when the first and last digits are erased.

How many numbers with such feature exist below 10000?

Clearly, no leading zeroes.

See The Solution Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Just counting (spoiler) | Comment 2 of 7 |
(In reply to Just counting (spoiler) by Steve Herman)

If the prohibition on leading zeros applies only to the 3- or 4-digit number itself, and not the internal 2-digit number, then there would be seven more, that is, 83, as the 1-digit  sums of squares would each account for both a 3-digit and a 4-digit number:


110    1010
121    1021
152    1052
240    2040
251    2051
282    2082
390    3090

Edited on July 17, 2017, 9:57 pm
  Posted by Charlie on 2017-07-17 13:53:40

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (11)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information