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Two sums of digits (Posted on 2017-09-02) Difficulty: 2 of 5
asd+fgh=jkl

Believe me - there are numerous solutions of the above alphametic.

I. What is the minimal possible sum of participating digits?
ii. Same question for as+df=gh

No Solution Yet Submitted by Ady TZIDON    
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Solution Part 2 (spoiler) | Comment 3 of 5 |
17 is the minimal possible sum.

For instance, 13 + 27 = 40

This is clearly better than using 1-6 (sums to 21), so we need a solution with a 0.

0 - 5 does not work because we need two digits that sum to 10.

0 1 2 3 4 6 Does not work.  Since we need a carry,  the sum of the digits must be odd.

And any other solution sums to more than 17.



  Posted by Steve Herman on 2017-09-02 12:55:52
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