The product of 3 brothers' ages is 567. Two are twins.

How old is the other one?

Let the age of the twins be x years while the age of the other

sibling is y years.

Then, by the problem, we have x^2* y = 567

Now, we observe that:

567

= 1^2*567

= 3^2*63

= 9^2*7

Since any person’s age cannot exceed 100, the first case is ruled out.

In the second case, the remaining sibling is 63, which makes him

60 years older than the twins( 3 years)

This is also impossible.

Consequently, the age of the twins must be 9 years while the other brother is 7 years old.