(In reply to
re: when it works -- computer exploration please edit by Ady TZIDON)
I've corrected the "n/2" to "(n/2)!", as pointed out by Ady.
I've finally understood chun's solution. I probably could have understood it earlier if an intermediate result had not been left out:
= 2*(1!)^2 * 2*(3!)^2 * 2*(5!)^2 * 2*(7!)^2 * ...... * 2*(97!)^2 * 2*(99!)^2
before the final equality. Students need the teacher to avoid leaving out intermediate steps, though some catch on faster.
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Posted by Charlie
on 2017-09-08 08:51:28 |
miscellany
