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Red vs Black Cuts (Posted on 2017-06-05) Difficulty: 3 of 5
A deck of 52 cards is shuffled and cut into two halves of 26 cards each. What is the probability that the number of red cards (hearts and diamonds) in the first half is equal to the number black cards (clubs and spades) in the second half?

Two jokers are added to the deck. The deck of 54 cards is shuffled and cut into two halves of 27 cards each. Now what is the probability that the number of red cards in the first half is equal to the number black cards in the second half?

See The Solution Submitted by Brian Smith    
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re: Solution | Comment 3 of 8 |
(In reply to Solution by Jer)

how did you get your probability of 27/53?  I am wondering where I may have gone wrong in my reasoning
  Posted by Daniel on 2017-06-05 09:37:22

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