Let's substitute each letter of a given word by the value of its ordinal count in the ABC: A=>1, B==>2 .. Z==>26.
Evaluate the total for that word and call it f(k), k being the number of letters in the word.
Let MW(K) be a word for which f(k) is minimal.
Example: assuming the word CAB generates the lowest f(3) then MW(3) is CAB and its f(3)=6.
Question: What triplet of common English words will generate the lowest
(In reply to computer solution
Therefore, cabbage, abandoned, abbreviated adds up to 21+60+89=170. The best solution is cabbage, bedabbled, abracadabra, which adds up to 21+37+52=110.
Posted by Math Man
on 2017-10-22 09:19:05