Prove every number in the sequence 38, 381, 3811, 38111, 381111, ... is composite.
If the number of 1's is 3*n+1, then the digits add up to 3*n+12. Therefore, the number is divisible by 3. If the number of 1's is 3*n+2, then the number is divisible by 37. Suppose the number of 1's is 3*n. Then, the number is ((343*(10^(3*n)))1)/9=(((7*(10^n))1)/3)*(((49*(10^(2*n)))+(7*(10^n))+1)/3). Therefore, the number is always composite.

Posted by Math Man
on 20170701 21:38:12 