 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Regular N-gon (Posted on 2017-07-09) n≥=3 lines lie in the same plane and are concurrent at point O.
If y = mx is the equation of a line passing through the origin O
(where m is the slope), then mk labels the line y = tan(k*180°/n)*x
(for k = 0 to n-1). Note: If n is even and k = n/2, then line mk is
perpendicular to line m0. Point P (distinct from O) is an arbitrary point
in the plane of the n lines. Fi is the foot of the perpendicular from
point P to line mi (for i = 0 to n-1).

Prove that F0F1...Fn-1 is a regular n-gon.

 No Solution Yet Submitted by Bractals Rating: 4.0000 (1 votes) Comments: ( Back to comment list | You must be logged in to post comments.) re: Solution Comment 2 of 2 | (In reply to Solution by Harry)

Hi Harry - you got the same results that I did.

One problem. I'm using GSP with n = 4.

If P lies between lines m_i & m_i+1, then

three of the angles show 45 degrees and

angle F_i+2 O F_i+3 shows 135 degrees

(modulo 4 on the subscripts).

 Posted by Bractals on 2017-07-10 07:25:50 Please log in:

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