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 Nondivisibility by 11 (Posted on 2017-08-06)
The number 545 has the curious property that — after replacing any single digit by another arbitrary digit (from 0 to 9; it can be a leading 0 or just the same digit) — the result is not divisible by 11.

Is there a positive integer with this property having an even number of digits?

 No Solution Yet Submitted by Danish Ahmed Khan Rating: 4.0000 (1 votes)

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I suspect all numbers with this nondivisibility have the form of ...ABABABA so that is what kind of numbers I will search for.

Call the number N. Let N mod 11 = R.

Changing one of the A digits will change the value of R.  The value of R will change directly with the change in A.  For nondivisibility by 11 to occur, the smallest value of R must be 1, occuring when the new digit is 0; and the largest value of R must be 10, occuring when the new digit is 9.  This then implies that N mod 11 = A+1.

Changing one of the B digits will also change the value of R.  The value of R will change inversely with the change in B.  For nondivisibility by 11 to occur, the smallest value of R must be 1, occuring when the new digit is 9; and the largest value of R must be 10, occuring when the new digit is 0.  This then implies that N mod 11 = 10-B.

Then N mod 11 = A+1 and N mod 11 = 10-B together imply A+1=10-B, or A+B = 9.  Then there are 10 cases to try.  For each case I list the smallest number I found in that case which has the nondivisibility property:

A,B=0,9: 909090909090
A,B=1,8: 1818181
A,B=2,7: 27272
A,B=3,6: 636363636363
A,B=4,5: 545454545454
A,B=5,4: 545
A,B=6,3: 636363636
A,B=7,2: 272727272727
A,B=8,1: 181818181818
A,B=9,0: 90909090909

This list has five 12-digit numbers with the nondivisibility by 11 property.

 Posted by Brian Smith on 2017-08-06 09:48:33

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