(1) First, A won from B as much as A had originally.
(2) Second, B won from C as much as B then had left.
(3) Finally, C won from A as much as C then had left.

The three players ended up with equal amounts of money.

Who began with 50 cents?

:Starting with k,k,k and going backwards we get

A: B: C = 3: 5:4

  SO   A must be a multiple of 3 and B OF 5   

 let k=20 to get the initial state  

   15,25,20                      è30,10,20è30,20,10è20,20,20

<      B    started with 25c                     >    

Edited on September 6, 2017, 6:34 pm

Posted by Ady TZIDON on 2017-09-06 18:10:31