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Just 4 different digits (Posted on 2017-12-03) Difficulty: 3 of 5
Let m*n=w (i)

m is a 3-digit number
so is n
w is a 6-digit number

In equation (i) only 4 distinct digits are used.

Find the possible equations.

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Hints/Tips re: Too many - here's some | Comment 2 of 10 |
(In reply to Too many - here's some by Jer)

I  admit that the multitude of solutions complying with the puzzle's requirements came as a total surprise to me .

However it is bound to happen now and then if neither the author nor the reviewers  solve the puzzle "comme il faut".
Still - there is a happy ending:
<begin a new puzzle - courtesy of jer> 
A 3-digit number   m and its square are expressed only by 4 distinct non-zero digits e.g. 472*472=222784  ==>     2,4,7,8 .
There are many numbers with this feature, however you are requested to find m such that both m-1  and m+1  need only
 4 non-zero digits  when concatenated with their respective squares.


Thanks, jer  - you like it and I like it too.

Now is Charlie's turn to establish whether this time it's a unique solution or not.


Edited on December 3, 2017, 11:24 am
  Posted by Ady TZIDON on 2017-12-03 11:19:22

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