Let

**m*n=w ** (i)

**m** is a 3-digit number

so is **n**

**w** is a 6-digit number

In equation (i) only 4 distinct digits are used.

Find the possible equations.

(In reply to

Too many - here's some by Jer)

I admit that the multitude of solutions complying with the puzzle's requirements came as a total surprise to me .

However it is bound to happen now and then if neither the author nor the reviewers solve the puzzle "*comme il faut".*

Still - there is a happy ending:

<begin a new puzzle - courtesy of jer>

A 3-digit number m and its square are expressed only by 4 distinct non-zero digits e.g. **472*472=222784** ==> **2,4,7,8** .

There are many numbers with this feature, however you are requested to find **m** such that both **m-1** and **m+1** need only

4 non-zero digits when concatenated with their respective squares.

<end>

Thanks, jer - you like it and I like it too.

Now is Charlie's turn to establish whether this time it's a unique solution or not.

HOO NOSE?

*Edited on ***December 3, 2017, 11:24 am**