All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 One problem - many ways to solve... (Posted on 2017-12-21)
The problem below (Moscow Puzzles #313) can be solved in more than 4 ways,
(each d1 by itself) - using different approaches.

Find the number t and the digit represented by k in:
[3*(230+t)]^2=492,k04

List your ways of solving it.

 No Solution Yet Submitted by Ady TZIDON No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
 Simple ways with calculator | Comment 1 of 6
[3*(230+t)]^2=492,k04

My first idea:
[3*(230+t)]^2 = 492,004 + 100k
3*(230+t) = 701.429968 + (a little bit)
230+t = 233.8099893 + (a little bit)
t = 3.8099893 + (a little bit)
guess t=4
confirm
[3*(230+4)]^2 = 492,804
so k=8

Second way (pretty similar)
492,k04 is a perfect square
square root of 492004 = 701.4
square root of 493004 = 702.1
702^2 = 492804
so k=8 and t follows.

 Posted by Jer on 2017-12-21 10:22:14

 Search: Search body:
Forums (0)