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 If two then three (Posted on 2017-10-14)
Prove that if

``` ac-b2    bd-c2
------ = ------
a-2b-c   b-2c+d
```
then both of the fractions are also equal to

``` ad-bc
-------
a-b-c+d```
(Assuming no divisions by zero, and b≠c.)

 No Solution Yet Submitted by Jer No Rating

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 Surely not Comment 1 of 1
There is some error in the formulation of this. I offer an example that shows the error.

Suppose a=2 b=6 c=4 d=3
Then
(ac-b^2)/(a-2b-c) = (8-36)/(2-12-4)=-28/-14=2

(bd-c^2)/(b-2c+d) = (18-16)/(6-8+3)= 2/1=2

So, both fractions are equal, but:

Differt from the two equal fractions.

This works only (with the example) if the numerator is ac-bd  instead of ad-bc, or if the denominator of the third fraction is -a instead of a.

Edited on February 2, 2018, 5:45 am
 Posted by armando on 2018-02-01 17:06:58

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