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2 Colors 2 (Posted on 2003-08-25) Difficulty: 4 of 5
Suppose you have an infinite plane, and each point on the plane has been arbitrarily painted one of two colors.

Prove that there exists an equilateral triangle whose vertices are all the same color.

What is the fewest number of points needed to prove this?

  Submitted by DJ    
Rating: 4.3684 (19 votes)
Solution: (Hide)
Five points are needed.

Take any two points that are of different colors; let's say that they are blue and orange.

The midpoint of the segment connecting the two points must be one of the two colors; therefore, it will match one of the vertices. Let's assume it is blue.

From the blue midpoint and the blue endpoint, there are two points equidistant from both, forming two equilateral triangles.

If either of these points is also blue, then they will, of course, form a monochromatic equilateral triangle. However, if both points are orange, they are vertices of another equilateral triangle, formed with the first orange point.

Therefore, there must exist an equilateral triangle whose vertices are all the same color, and we have proven this using only five points.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Puzzle Thoughts K Sengupta2023-05-12 22:44:54
selecting pointskeiko2004-06-27 18:41:15
No SubjectB M2003-09-29 04:46:38
re(3): 5-point proof - to DJCharlie2003-09-21 16:34:10
Questionre(2): 5-point proof - to DJaln2003-09-20 23:12:44
How about ...Lawrence2003-08-30 20:42:11
re(4): 5-point proofDJ2003-08-26 21:14:49
re(3): 5-point proofKelsey2003-08-26 20:59:23
Some Thoughtsre(2): 5-point proofDJ2003-08-26 16:51:48
re(2): 5-point proofKelsey2003-08-26 15:39:07
re: 5-point proofKelsey2003-08-26 15:29:18
Solution5-point proofBryan2003-08-26 10:59:20
Another proofBrian Wainscott2003-08-25 17:35:34
Some Thoughtsa proofCharlie2003-08-25 13:17:23
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