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15=5*3 (Posted on 2018-03-01) Difficulty: 3 of 5
(1,8,15);(2,7,12);(3,4,5);(6,10,14);(9,11,13).
The above line represents grouping of the first 15 integers into disjoint subsets of 3 elements, each triplet being an ascending arithmetic progression - each triplet with unique difference.
List all possible groupings into 5 triplets - each grouping with another set of 5 distinct differences.
Order the triplets by the value of the 1st element, like in the example shown.

  Submitted by Ady TZIDON    
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Solution: (Hide)
a. 1 8 15; 2 7 12; 3 4 5; 6 10 14; 9 11 13.
b. 1 8 15; 2 6 10; 3 5 7; 4 9 14; 11 12 13.
a.- solution given as an example in the text of the puzzle.
b.- all numbers are 16-complements of the sample numbers in a.

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  Subject Author Date
Solutioncomputer solutionCharlie2018-03-01 15:40:50
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