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One square implies many (Posted on 2018-03-28) Difficulty: 2 of 5
Prove the following:
If there is one perfect square in an arithmetic progression, then there are infinitely many.

No Solution Yet Submitted by Ady TZIDON    
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re: Counterexample | Comment 2 of 6 |
(In reply to Counterexample by Steve Herman)

Even in the positive reals: 4+pi, 4+2pi,.... I rather doubt there is another square in the sequence.

A different matter if a and d are both in the positive integers.

Update: it's also true if a and d are in the positive rationals.

Edited on March 28, 2018, 9:30 am
  Posted by broll on 2018-03-28 08:52:00

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