All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Squares built from leftovers (Posted on 2018-04-05) Difficulty: 2 of 5
Let N1=123456789
Erase n digits and shrink the remnants of N1 into one continuous chain creating a new number N1'.

What is the minimum number of digits to be erased so that N1' will be a square number?

Same question for N2=987654321 and N2'.

See The Solution Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution by cheating | Comment 2 of 4 |
If you consider looking up the numbers on OEIS to be cheating.
I found the numbers up to 3 digits then searched and found
http://oeis.org/A122683
The largest number is 134689, three digits erased

http://oeis.org/A124683
The largest number is 961, six digits erased. 
(I'm surprised at having to erase so many.) 

Edited on April 5, 2018, 2:54 pm
  Posted by Jer on 2018-04-05 14:33:51

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (17)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information