On a circumference of a given circle with a radius R two random points A & B are independently chosen.
What is the probability of AB being less than R ?
(In reply to
re(2): There must be a reason for the D3 rating. by Ady TZIDON)
Your mention of a probability of 1/4 struck me. I couldn't (and still can't) imagine the probability would be less than 1/3, as any concentration of points in particular area(s) would only increase the probability of proximity.
You mentioned Bertrand's paradox in relation to this. The example that came up was with choosing a random chord--not the same thing as independently choosing two random points. Here's the description that leads to a probability of 1/3:
The "random midpoint" method: Choose a point anywhere within the circle and construct a chord with the chosen point as its midpoint. The chord is longer than a side of the inscribed triangle if the chosen point falls within a concentric circle of radius 1/2 the radius of the larger circle. The area of the smaller circle is one fourth the area of the larger circle, therefore the probability a random chord is longer than a side of the inscribed triangle is 1/4.
However, using the endpoints of this chord as the two points means that the two points have not been chosen independently; it is the chord that is chosen randomly, with the endpoints of that chord chosen as the two points--they are not independent.
|
|
Posted by Charlie
on 2018-04-26 12:04:02 |
re(3): There must be a reason for the D3 rating.
