Take an isosceles triangle and its inradius r
_{1}. Split the triangle by its altitude. The radius of one of these smaller triangles is r
_{2}.
If r_{1}/r_{2}=3/2 what is the ratio of base to height in the original triangle?
The inradius is a perpendicular to each side of a triangle so Area = 1/2 * inradius * (sum of sides).
If the isosceles triangle has sides (a,a,2b) then its area = 1/2 * r1 * (2a+2b) = twice area of split triangle = 2 * 1/2 * r2 * (a+b+h). Given r1/r2 =3/2, this reduces to a+b=2h.
From the halftriangle b^2 + h^2 = a^2. Substitute a=b2h to get 4b=3h and 2b/h = 3/2.

Posted by xdog
on 20180203 16:06:13 