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 Sort it out ! (Posted on 2018-06-05)
A woman bought something costing 34c.
She only had 3 coins: \$1, 2c and 3c.
The shopkeeper had only 2 coins: 25c and 50c.
Fortunately another customer had 5 coins: 2*10c, a 5c coin, 2c coin and a 1c coin.

How did they resolve the purchase?

 No Solution Yet Submitted by Ady TZIDON No Rating

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 A solution Comment 1 of 1
There may be more than one solution, but here's the first I found.

Customer must end up with (100+2+3)-34=71 cents
Shopkeeper must end up with (25+50)+34=109 cents
The helper must end up with (10*2+5+2+1)=28 cents

Pool the money (rather than worry about who gives money to who) then it's easy for each person to take what they need.

Customer takes 50+10+10+1
Shopkeeper takes 100+5+2+2
Helper takes 25+3

 Posted by Jer on 2018-06-05 09:18:43

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