Find a sixdigit number
ABCDEF such that
AB^{3}+CD^{3}+EF^{3}=ABCDEF.
Rem: VWXYZ denotes the value of the string (not necessarily distinct digits).
(In reply to
computer solution by Charlie)
Given the standard definition of an ndigit number the A in the numeric strings ABCDEF must be a nonzero digit and each of A, B, C, D, E, and F are decimal digits yet there is no more than an assumption that the C and E digits are also nonzero digits. Given that these twodigit strings can have leading zeroes, the following five solutions can be included with the seven already given:
336700
336701
340067
407000
407001
If each digit were given as distinct, there are two solutions:
341067
487215

Posted by Dej Mar
on 20180612 22:50:09 