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Palindrome in 4 steps (Posted on 2018-06-06) Difficulty: 3 of 5
I took a certain 3-digit number, reversed it, got another 3-digit number, and added the two.
The sum was not a palindrome.
I repeated the process, which resulted in another 3-digit number that was still not a palindrome.
Repeating the process twice more I got a 4-digit number, which was a palindrome finally.

What was the 3-digit number we started with the second time?

No Solution Yet Submitted by Ady TZIDON    
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re: computer findings (spoilers) | Comment 2 of 4 |
(In reply to computer findings (spoilers) by Charlie)

perhaps I am reading it wrong, but in the first part it is stated that the reversed number is also 3 digits.  So that would eliminate 280,290, and 390 as starting numbers which in turn eliminates 362 and 382 as the second number.  Thus it would seem that 483 is the only possible value for the second number with either 192 or 291 leading to that number.
  Posted by Daniel on 2018-06-06 14:49:31

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