I took a certain 3digit number, reversed it, got another 3digit number, and added the two.
The sum was not a palindrome.
I repeated the process, which resulted in another 3digit number that was still not a palindrome.
Repeating the process twice more I got a 4digit number, which was a palindrome finally.
What was the 3digit number we started with the second time?
(In reply to
re: computer findings (spoilers) by Daniel)
Given that the reversal of the initial 3digit number is another 3digit number, it is implied that the reversed number is different than the original. This assumption eliminates both 181 and 191 being the original numbers, yet it can be argued that that assumption should not necessarily be made as the related subject is palindromes.
181 + 181 = 362
362 + 263 = 625
625 + 526 = 1151
1151 + 1511 = 2662
191 + 191 = 382
382 + 283 = 665
665 + 566 = 1231
1231 + 1321 = 2552
As there is an implication that there is but one number as the solution, the assumption will be applied.
192 + 291 = 483, as
291 + 192 = 483
483 + 384 = 867
867 + 768 = 1635
1635 + 5361 = 6996
The 3digit number of the initial sum is 483.

Posted by Dej Mar
on 20180607 04:05:22 