 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Palindrome in 4 steps (Posted on 2018-06-06) I took a certain 3-digit number, reversed it, got another 3-digit number, and added the two.
The sum was not a palindrome.
I repeated the process, which resulted in another 3-digit number that was still not a palindrome.
Repeating the process twice more I got a 4-digit number, which was a palindrome finally.

What was the 3-digit number we started with the second time?

 No Solution Yet Submitted by Ady TZIDON No Rating Comments: ( Back to comment list | You must be logged in to post comments.) re(2): computer findings (spoilers) Comment 4 of 4 | (In reply to re: computer findings (spoilers) by Daniel)

Given that the reversal of the initial 3-digit number is another 3-digit number, it is implied that the reversed number is different than the original. This assumption eliminates both 181 and 191 being the original numbers, yet it can be argued that that assumption should not necessarily be made as the related subject is  palindromes.
181 + 181 = 362
362 + 263 = 625
625 + 526 = 1151
1151 + 1511 = 2662
191 + 191 = 382
382 + 283 = 665
665 + 566 = 1231
1231 + 1321 = 2552

As there is an implication that there is but one number as the solution, the assumption will be applied.

192 + 291 = 483, as
291 + 192 = 483
483 + 384 = 867
867 + 768 = 1635
1635 + 5361 = 6996
The 3-digit number of the initial sum is 483.

 Posted by Dej Mar on 2018-06-07 04:05:22 Please log in:

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