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Maximum Value (Posted on 2002-06-19) Difficulty: 3 of 5
We have :
      x^2+xy+y^2=3 and
      y^2+yz+z^2=16
      A=xy+yz+zx
Find the maximum value of A. Find x, y and z when A=max value.

(Remember the category)

See The Solution Submitted by vohonam    
Rating: 3.2857 (7 votes)

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Some Thoughts No Subject | Comment 10 of 19 |
x=1, y=1, z=(-1+SQRT(61))/2 A=SQRT(61)
x=-1, y=-1 z=(1-SQRT(61))/2 A=SQRT(61)
  Posted by lucky on 2002-06-23 07:48:58
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