Maximum Value (Posted on 2002-06-19)

      x^2+xy+y^2=3 and
      y^2+yz+z^2=16
      A=xy+yz+zx

	Submitted by vohonam
Rating: 3.2857 (7 votes)
Solution:	(Hide)
The maximum value is 8. There are two sets of values that yield this value: (x, y, z) = (7/√31, 4/√31, 20/√31) and (x, y, z) = (-7/√31, -4/√31, -20/√31) Brian Smith offers a three-part solution here, here, and here.

	Subject	Author	Date
	Puzzle Answer	K Sengupta	2022-04-12 01:56:47
	Solution: Part 3	Brian Smith	2003-09-04 12:01:53
	Solution: Part 2	Brian Smith	2003-09-04 11:46:19
	Solution: Part 1	Brian Smith	2003-09-04 11:15:27
	re: Most of a solution - Solution confimed.	Brian Smith	2003-04-28 04:13:15
	re(2): Most of a solution	Brian Smith	2003-04-09 05:29:11
	re: Most of a solution	Cory Taylor	2003-04-09 04:21:56
	Most of a solution	Brian Smith	2003-04-08 09:59:54
	re: Who can do this ?	Cory Taylor	2002-11-15 03:56:38
	No Subject	lucky	2002-06-23 07:48:58
	Who can do this ?	vohonam	2002-06-20 18:22:23
	re: Methods to solve this	vohonam	2002-06-19 17:28:58
	Methods to solve this	vohonam	2002-06-19 17:27:00
	re(3): Oooo... Getting schmancy, are we?	friedlinguini	2002-06-19 08:12:06
	re(2): Oooo... Getting schmancy, are we?	levik	2002-06-19 07:48:07
	re: Oooo... Getting schmancy, are we?	friedlinguini	2002-06-19 06:59:47
	re(2): Oooo... Getting schmancy, are we?	friedlinguini	2002-06-19 05:00:25
	re: Oooo... Getting schmancy, are we?	levik	2002-06-19 04:36:53
	Oooo... Getting schmancy, are we?	friedlinguini	2002-06-19 04:18:57