There is a vertical pole perpendicular to the horizontal plane. From point P on the plane, 2 projectiles are fired simultaneously at different velocities. The first projectile is fired at an angle of 30o and it hits the foot of the pole. The second projectile is fired at an angle of 60o and it hits the top of the pole
It is further known that the projectiles hit the pole at the same time.
Find the angle subtended by the pole from P.
i get
(note that the projectiles are going one above the other, so same velocity projection to earth)
h/a=tg60-tg30
h=height vertical pole
a=distance from point P to the pole
Angle theta = arctg h/a= 16,10°
Edited on March 23, 2018, 6:33 pm
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Posted by armando
on 2018-03-23 18:18:17 |
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