All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Sum of 4 squares (Posted on 2018-07-08) Difficulty: 3 of 5
The number N is a sum of 4 different numbers, each being a square of one of the 4 smallest divisors of N (e.g. N=36 does not qualify since 1^2+2^2+3^2+4^2
sums up to 30, not 36.)

Provide a full list of similar numbers or show that none exist.

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
thoughts | Comment 2 of 4 |
Yeah, that's about it, as I found too. Here is where I got on the proof.
(not far)
N must be even, else only odd divisors squared (odd) would add to even. So 1st 2 divisors are 1 and 2. The last two, a and b have a^2 + b^2 = N-5, which is odd. So only one of the squares is odd, and this means only one of a and b are odd. Calling d the even one then d might = 2e with e prime and after trying 2(3) we see 2(5) works. But why must e be prime is where I am stuck, Cheers
 

Edited on July 8, 2018, 4:08 pm
  Posted by Steven Lord on 2018-07-08 16:07:38

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information