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Probability of being coprime (Posted on 2018-07-11) Difficulty: 3 of 5
What is the probability of two randomly chosen integers being coprime?

Bonus(d4): How does the result relate fo the density
of square-free numbers?

No Solution Yet Submitted by Ady TZIDON    
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Solution re: computer approximation (vs researched solution) | Comment 2 of 4 |
(In reply to computer approximation by Charlie)

Researching this problem shows the actual answer is 6 / pi^2. This evaluates to approximately  .607927101854028, so there was more accumulated rounding error, combined with probably factor values left out at the cutoff, than I had allowed for in my claimed choice of precision representation.

Edited on July 11, 2018, 11:56 am
  Posted by Charlie on 2018-07-11 11:56:00

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