 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Complex (Posted on 2018-12-22) A = 1 + x3/3! + x6/6! + x9/9! + ...
B = x + x4/4! + x7/7! + x10/10! + ...
C = x2/2! + x5/5! + x8/8! + x11/11! + ...

Find the value of A3 + B3 + C3 - 3ABC.

 No Solution Yet Submitted by Danish Ahmed Khan Rating: 4.0000 (1 votes) Comments: ( Back to comment list | You must be logged in to post comments.) Differential equation | Comment 2 of 3 | A(x) is the derivative of B(x), similarly B(x) is the derivative of C(x) and C(x) is the derivative of A(x).  Then all three are specific solutions to the general differential equation y - y''' = 0.

The general solution to y - y''' = 0 is y(x) = k1*e^x + k2*e^(-x/2)*cos(sqrt(3)x/2) + k3*e^(-x/2)*sin(sqrt(3)x/2), with parameters k1, k2, k3.

Then it would be possible to construct the explicit formulas for A(x), B(x), and C(x) by finding the appropriate coefficients k1, k2, and k3.

 Posted by Brian Smith on 2018-12-26 01:03:00 Please log in:

 Search: Search body:
Forums (1)