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Sine recurrence (Posted on 2019-01-08) Difficulty: 3 of 5
If a0 = sin2 (π/45) and an+1 = 4an(1 - an) for n >= 0, find the smallest positive integer n such that an = a0

No Solution Yet Submitted by Danish Ahmed Khan    
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re(2): @ DAK | Comment 3 of 6 |
(In reply to re: @ DAK by Charlie)


I assumed it is Pi, however wanted to be sure.

  Posted by Ady TZIDON on 2019-01-08 10:06:31
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