perplexus.info :: Just Math : Sine recurrence

Sine recurrence (Posted on 2019-01-08)

If a₀ = sin² (π/45) and a_n+1 = 4a_n(1 - a_n) for n >= 0, find the smallest positive integer n such that a_n = a₀

No Solution Yet Submitted by Danish Ahmed Khan

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re: Full solution...............kudos

Comment 6 of 6 |

(In reply to Full solution by Jer)

Brilliant logic!

I've got the same result - using EXCELL spread sheet.

Saw no point of posting it after Charlie's solution.

Posted by Ady TZIDON on 2019-01-09 03:23:54

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