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Sine recurrence (Posted on 2019-01-08) Difficulty: 3 of 5
If a0 = sin2 (π/45) and an+1 = 4an(1 - an) for n >= 0, find the smallest positive integer n such that an = a0

No Solution Yet Submitted by Danish Ahmed Khan    
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Some Thoughts re: Full solution...............kudos Comment 6 of 6 |
(In reply to Full solution by Jer)

Brilliant logic!


I've got the same result - using EXCELL spread sheet.
Saw no point of posting it after Charlie's solution.



  Posted by Ady TZIDON on 2019-01-09 03:23:54
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