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More or less 6 days (Posted on 2019-01-24) Difficulty: 3 of 5
<begin>
A student has a book containing 411 pages.

She read a certain number of pages on the first day and created a rule to work out how many pages she had to read on each succeeding day.
She decided that the number of pages to be read on the next day should be equal to the square of the sum of the digits of the page she ended at.
She found that on the sixth day, the number of pages she had set herself to read took her exactly to the final page of the book.
How many pages did she read on the 1st day?
<end>
The above puzzle comes from a Cambridge University publication.

My question: list all the possibles scenarios , completing the book not necessarily in 6-day period, but still adherring to her rules.

See The Solution Submitted by Ady TZIDON    
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re(2): computer solution--all ways | Comment 4 of 6 |
(In reply to re: computer solution--all ways by Steve Herman)

Indeed I misread, or forgot while solving, the rules. 


Corrected set:

13 5     13 16 121 36 225
16 4     16 49 121 225
29 4     29 121 36 225
61 6     61 49 4 36 36 225
65 3     65 121 225
110 5     110 4 36 36 225
114 4     114 36 36 225
150 3     150 36 225
186 2     186 225
190 3     190 100 121
241 3     241 49 121
290 2     290 121
411 1     411

In the program listing

      dr$ = LTrim(Str(totread))

replaces

      dr$ = LTrim(Str(dread))

so that the number to be squared is the total read so far (i.e., the number of the last page read), rather than the number read on the preceding day.

  Posted by Charlie on 2019-01-25 12:53:28
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