See the problem as posed originally here.
Triangle T has area A and sides of length a,b, and c.
Given 3 concentric circles of radius a,b,c, respectively, find the areas of the largest and smallest equilateral triangles with a vertex on each circle in terms of the given variables.
The smallest one is very easy as the minimum lengtht of the triangle with a vertex on each circle is c-a
Smallest: A=[(c-a)^2]/2. [Att: This is wrong[
Largest: It's difficult to find by oneself, but there is a formula for equilateral triangles
A= (1/2)*[(sqr3/4)*(a^2+b^2+c^2) + 3 Area T (abc)]
All this are known, so thats the solution
And I congratule for the one hundred number.... (to broll)
Edited on January 6, 2019, 11:21 am
Edited on January 12, 2019, 4:58 am
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Posted by armando
on 2019-01-06 11:20:10 |
solution
