A cube on a table has edge length 24. A plane intersects the cube's four vertical edges at points A, B, C, and D such that point A is a vertex of the cube lying on the table. The heights of points B and C from the table floor are 7 and 12, respectively.
Calculate the volume of the portion of the cube that lies underneath the cutting plane.
Assuming A, B, C and D are either in clockwise or anticlockwise order (B and C on adjacent vertical cells):
The plane is linear in z as a function of x and y (taking the base of the cube as lying on the z = 0 plane).
We have a point at (0,0,0); another at (24,0,7); another at (34,34,12). The fourth is at (0,24,5), with the 5 having been calculated as the same distance above zero as 12 is above 7.
Taking one face of the block whose volume is to be found as the right triangle with legs of length 24 and 5, and the opposite face as the trapezoid with edge 7 opposite that with length 12, the crosssectional area, increases linearly from 60 at the former face to 228 at the latter face.
The average cross section is therefore 144 square units. Multiplied by the 24unit length we get 3456 as the volume of the block.

Posted by Charlie
on 20190213 12:25:24 