How would you divide a line segment in the ratio 2 - √3 : 2 + √3 using only a compass and straightedge?
Call the segment AE. Bisect the segment and call the midpoint C. Bisect AC and CE. Then we have 5 points ABCDE. Call the spacing between them 1 unit.
Draw circles at E containing D and D containing E. Call one of their intersections X. CX=√3.
Draw the circle at C containing X. This intersects the segment at Y.
AY= 2 + √3and YE=2 - √3
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Posted by Jer
on 2019-03-05 09:49:34 |
Solution
