All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Origamic (Posted on 2003-09-23) Difficulty: 3 of 5
A rectangular sheet of paper is folded so that two diagonally opposite corners come together. The crease thus formed is as long as the longer side of the rectangle.

What is the ratio of the longer side of the rectangle to the shorter?

See The Solution Submitted by DJ    
Rating: 4.4167 (12 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Out on a Limb Comment 11 of 11 |

Ok this is probably not even close to the answer but I work better with numbers. Okay here goes: 1/4 : 1 (1 being the longer side, 1/4 being the shorter).

I thought about it for a while then got a head ache so thought it might be an easy answer since I wasn't given any numbers. I took the original numbers to be 1/2 : 1 (for every one the shorter side would be half that.) So folding it in half gives you a quarter, for every one the shorter side would be a quarter of that. If 1 = 20, then 1/4 = 5. Or something like that

Raika ^.^


  Posted by Raika on 2005-05-22 02:16:20
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2014 by Animus Pactum Consulting. All rights reserved. Privacy Information