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Factor hints II (Posted on 2019-04-20) Difficulty: 2 of 5
399337 = 6162 + 1412
399337 = 4642 + 4292

Based on the above results find the two prime factors of 399337.

No Solution Yet Submitted by Danish Ahmed Khan    
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Longhand Comment 1 of 1
Using a method of Euler:

Let a=616, b=141, c=464, d=429

Then
a-c=152  2^3*19
a+c=1080 2^3*3^3*5
d-b=288  2^5*3^2
d+b=570  2*3*5*19
GCD(152,288)=8
GCD(1080,570)=30
GCD(152,570)=38
GCD(1080,288)=72
399337=((8/2)^2+(30/2)^2)*((38/2)^2+(72/2)^2) = 241*1657 

  Posted by broll on 2019-04-22 10:56:40
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