All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Just substitute? (Posted on 2019-09-17) Difficulty: 1 of 5
Find the value of x5-100x4+100x3-100x2+100x-9 when x = 99.

No Solution Yet Submitted by Danish Ahmed Khan    
Rating: 3.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution | Comment 1 of 3
x^5-100x^4+100x^3-100x^2+100x-9
= (x^5-99x^4) + (-x^4+99x^3) + (x^3-99x^2) + (-x^2+99x) + x-9
= (x-99)*(x^4-x^3) + (x-99)*(-x^3+x^2) + (x-99)*(x^2-x) + (x-99)*(-x+1) + x-9
= 0*(99^4-99^3) + 0*(-99^3+99^2) + 0*(99^2-99) + 0*(-99+1) + 99-9
= 90

  Posted by Brian Smith on 2019-09-17 13:04:10
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (14)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information