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A positive rational function (
Posted on 20191101
)
Let Q' denote the set of all positive rational numbers. If f:Q'→Q' satisfies
f(x
^{2}
f(y)
^{2}
)=f(x)
^{2}
f(y),
evaluate f(2019).
No Solution Yet
Submitted by
Danish Ahmed Khan
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one solution
 Comment 1 of 3
f(x)=1 is a solution
f(x^2*f(y)^2)=1
and
f(x)^2*f(y)=1^2*1=1
not able to find a proof that this is the only solution
Posted by
Daniel
on 20191101 10:17:10
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