991

The following program simulates long division taking the digits 2 at a time, but only keeps track of the remainder.

digits = 4018
location = 0
remainder = 0
while digits>0:
    divisor = remainder*100 + 23
    remainder = divisor % 999
    location += 2
    digits -= 2

print(location,remainder)

Output:  4018 991

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Also note that the remainders follow a repeating pattern of period 27.

(but if you did this one digit at a time, I expect the cycle would be of period 54)