Given a reference triangle △ABC, a reflection triangle △A′B′C′ is generated by reflecting each vertex about the opposite side, for example A′ is generated by reflecting vertex A about side BC. Now, suppose the vertices A′, B′ and C′ are given, how can you find the original vertices of the original triangle △ABC?
(In reply to
re: What am I missing? -> The Kosnita Point by Steven Lord)
Right, theorem 4 clears it up. So we "simply" construct the nine-point center N (see
here), draw its pedal triangle, construct the centroid G, then throw the pedal triangle into the h(G,4) homothety and - quite effortlessy - we have A', B' and C'.
Sometimes it's so easy ;)
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Posted by JLo
on 2020-01-27 05:52:34 |
re(2): What am I missing? -> The Kosnita Point
