Construct equilateral triangle ABC and square BCDE with point A outside the square. A circle is drawn containing A, D and E. How does the radius of the circle compare to the side length of the triangle?
Repeat the above but with point A inside the square.
Presumably, you mean the smallest possible circle, otherwise it is hard to see how the circles are uniquely specified.
With A inside the square, the radius is half the square's diagonal, or BC/root(2).
With A outside the circle, the radius is AE/2 or BC/root(8) + BC root(3/8)
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Posted by FrankM
on 2020-04-13 09:57:42 |
Solution
