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Division by e (Posted on 2020-03-25) Difficulty: 4 of 5
Let [x] denote the closest integer to x.

Find the last 5 digits of [100000!/e]

No Solution Yet Submitted by Danish Ahmed Khan    
Rating: 5.0000 (2 votes)

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Some Thoughts Surprising consequence | Comment 7 of 10 |
Brian's solution implies just a little bit of regularity in the number 1/e.  Every (10^n)! there is a string of n 0's before the decimal.  Using Wolfram|Alpha you can confirm this up to n=4.

It looks like this would also be the case in other bases as well.

  Posted by Jer on 2020-03-29 19:10:39
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