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7 matches (Posted on 2020-07-15) Difficulty: 3 of 5
Set A consists of 8 words: (face,hear,know,land,lover,olive,overt,seven)
Set B as well:
(seize,story,pride,iron,there,easy,table,tubal)

Let us match each word of set A with such a word from set B, that by erasing one letter from each and joining them together a new valid word is formed and matches will be found for all.

To make things clear I match
FACE & STORY to create FACTORY.

Now you match all others.

No Solution Yet Submitted by Ady TZIDON    
Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution computer solution | Comment 2 of 3 |
DefDbl A-Z
Dim crlf$, setA$(8), setB$(8)
 

Private Sub Form_Load()
 Text1.Text = ""
 crlf$ = Chr(13) + Chr(10)
 Form1.Visible = True
  
  setA(1) = "face"
  setA(2) = "hear"
  setA(3) = "know"
  setA(4) = "land"
  setA(5) = "lover"
  setA(6) = "olive"
  setA(7) = "overt"
  setA(8) = "seven"
  
  setB(1) = "seize"
  setB(2) = "story"
  setB(3) = "pride"
  setB(4) = "iron"
  setB(5) = "there"
  setB(6) = "easy"
  setB(7) = "table"
  setB(8) = "tubal"
  
  For a = 1 To 8
  For b = 1 To 8
   If a = 1 And b = 2 Then
     xx = xx
   End If
    For i = 1 To Len(setA(a))
    For j = 1 To Len(setB(b))
      w$ = Left(setA(a), i - 1) + Mid(setA(a), i + 1) + Left(setB(b), j - 1) + Mid(setB(b), j + 1)
      If isWord(w) Then
        Text1.Text = Text1.Text & setA(a) & " "
        Text1.Text = Text1.Text & setB(b) & " "
        Text1.Text = Text1.Text & w & crlf
      End If
      
      w$ = Left(setB(b), i - 1) + Mid(setB(b), i + 1) + Left(setA(a), j - 1) + Mid(setA(a), j + 1)
      If isWord(w) Then
        Text1.Text = Text1.Text & setA(a) & " "
        Text1.Text = Text1.Text & setB(b) & " "
        Text1.Text = Text1.Text & w & crlf
      End If
      
    Next
    Next
  Next
  Next
  Text1.Text = Text1.Text & crlf & "done"
End Sub

Function isWord(x$)
DoEvents
w$ = Space$(Len(x$))
l = Len(x$)
If l = 0 Then isWord = 0: Exit Function
Open "\words\words" + LTrim$(Str$(l)) + ".txt" For Binary As #10
low = 1: high = LOF(10) / l
Do
    midl = Int((high + low) / 2)
    Get #10, (midl * l) + 1 - l, w$
    If w$ = x$ Then Exit Do
    If w$ > x$ Then high = midl - 1
    If w$ < x$ Then low = midl + 1
Loop Until high < low
If w$ = x$ Then isWord = 1 Else isWord = 0
Close 10
End Function

finds

face story factory
face tubal factual
hear there heather
hear easy heresy
know there nowhere
land iron ladron
lover seize oversize
lover pride override
lover table overable
lover table loveable
olive table liveable
overt seize oversize
overt pride override
overt table overable
seven tubal eventual

but presumably what's wanted is a 1-to-1 correspondence between the two sets of words.

We can start with

face story factory (given; also, it leaves tubal available to seven to make eventual)
know there nowhere
land iron ladron  (a robber or pirate, usually spelled ladrone in English)
olive table liveable
seven tubal eventual

then

hear easy heresy

but lover and overt can dispute who gets seize and who gets pride:

lover seize oversize
overt pride override

or 

lover pride override
overt seize oversize

  Posted by Charlie on 2020-07-15 22:52:22
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