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Check this sequence (Posted on 2020-08-24) Difficulty: 2 of 5
6,10,14,15,21,22,....ad inf

This sequence consists of products of two distinct primes.


1. What is the 1st appearance of 3 successive numbers?
2. How many triplets like n, n+1, n+2 are there below 2000?
3. Prove that 4 numbers in a succession cannot appear in this sequence.

No Solution Yet Submitted by Ady TZIDON    
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Solution parts 1 & 2 - computer solution Comment 3 of 3 |
 33   34   35   3       ... the first
 85   86   87   3 
 93   94   95   3 
 141   142   143   3 
 201   202   203   3 
 213   214   215   3 
 217   218   219   3 
 301   302   303   3 
 393   394   395   3 
 445   446   447   3 
 633   634   635   3 
 697   698   699   3 
 921   922   923   3 
 1041   1042   1043   3 
 1137   1138   1139   3 
 1261   1262   1263   3 
 1345   1346   1347   3 
 1401   1402   1403   3 
 1641   1642   1643   3 
 1761   1762   1763   3 
 1837   1838   1839   3 
 1893   1894   1895   3 
 1941   1942   1943   3 
 1981   1982   1983   3, 
 
 
 a total of 24 occurrences below 2000, from:

    4   kill "nsqsmprm.txt"
    5   open "nsqsmprm.txt" for output as #2
   10   for N=6 to 2000
   20      Pd=prmdiv(N)
   30      Q=N//Pd
   40      if prmdiv(Q)=Q and Q<>Pd and Q>1 then InRow=InRow+1:else InRow=0
   50      if InRow>2 then print N,InRow:print #2,N-2,N-1,N,InRow:inc Ct
   60   next
   65   print Ct:print #2,Ct
   70   close #2
  999   end


  Posted by Charlie on 2020-08-24 20:07:33
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