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 50 - or more (Posted on 2020-09-10)
Let's start with a triplet of integers, say (1, 2, 5) and a set of mathematical operations (+, -, *, /, ^, sqrt, fact!, concatenation, brackets).

Our task will be to represent all (or almost all - as explained below) integers from 1 to n using some or all of the initial triplet and any quantity of operations defined above.

So:
1=1
6=1+5
9=5*2-1
13=15-2
27=51-4!
60=12*5 etc

Let's define n as the first occurrence of not being able to find a valid representation for n+1 and for n+2. I believe that in our case n=17 (15+2), since neither 18 nor 19 get valid solutions.

You are requested to find a triplet of integers (a,b,c) enabling a maximal n.

 No Solution Yet Submitted by Ady TZIDON No Rating

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 50 - or more | Comment 12 of 14 |
99+(sqrt9)
Replace 9 by !4
Seems like 105 is our limit.

Personally, I think that this is how this problem is solved. Although I find it difficult, it's not as hard as choosing the

 Posted by Kathie on 2020-09-15 16:10:04

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