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 Quick divisibility (Posted on 2020-10-20)
Find all possible digits x, y, z such that the number 13xy45z is divisible by 792.

 No Solution Yet Submitted by Danish Ahmed Khan Rating: 5.0000 (1 votes)

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 Solution | Comment 1 of 3
To be divisible by 792, a number must be divisible by 8 and 99. Then, the last 3 digits are divisible by 8. The only digit z such that 45z is divisible by 8 is 6. Therefore, z=6 and the number ends in 456. Since 13xy456 is divisible by 99, the sum of the digits in pairs is divisible by 99. Then, 1+3x+y4+56 is divisible by 99. The only possibility is 1+38+04+56=99. Therefore, x=8 and y=0. Then, the number is 1380456=792*1743.

 Posted by Math Man on 2020-10-20 09:25:29

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