Please find all real solutions to the following equation:
(x^211*x+29)^(x^217*x+72) = 1
Adapted from a problem by Presh Talwalkar.
Either
x^211*x+29 = 1
or
x^217*x+72 = 0
first case:
x^2  11x + 28 = 0
x = (11 +/ sqrt(121  112))/2 = (11 +/ 3) = 4 or 7
second case:
x = (17 +/ sqrt(289  288))/2 = 8 or 9
So the solution set is {4, 7, 8, 9}.

Posted by Charlie
on 20210406 10:59:00 